Date formatting - UNIX for Dummies Questions & Answers

knc9233 · #1 01-12-2007

Running bash how do I input the date in the command line like 3/20/90 and get an output formmated like March, 20 1990.

Yogesh Sawant · #2 01-15-2007

this works for me:

Code:

[ysawant@anamika ysawant]$ date +'%B, %d %G' --date="3/20/90"
March, 20 1990
[ysawant@anamika ysawant]$

knc9233 · #3 01-15-2007

thanks. that worked. do you know how I would make it work so if 13 was inputed as the month it would print an error?

zazzybob · #4 01-15-2007

An error like this?

Code:

$ date +'%B, %d %G' --date="13/20/90"
date: invalid date `13/20/90'

You could also do something like this:

Code:

$ date +'%B, %d %G' --date="13/20/90" 2>/dev/null || echo "ERROR"
ERROR
$ date +'%B, %d %G' --date="3/20/90" 2>/dev/null || echo "ERROR"
March, 20 1990

Cheers
ZB

knc9233 · #5 01-15-2007

when i input a month of 13 now i get it bumped to january. i do the input from the command line, so i need to read the month from there and determine if it is over 12 and display an error stating that the month inputed does not exist.

Krrishv · #6 01-15-2007

#! /usr/bin/ksh
echo -p "Enter the Input date format : \c"
read t
m=`echo $t|cut -d "/" -f1`
if [ $m -lt 13 ]; then
date +'%B, %d %G' --date="$t"
else
echo "Not a Valid Month"
exit 0
fi

knc9233 · #7 01-16-2007

yeah not looking for an input line want it right off the command line. (shell scriptname date)

i'm trying to use IFS and separate the input by the "/". script currently looks like...
#!/bin/bash

{ [ $# -eq 1 ] &&
[ -d "$1 ]; } || {
echo "Must Input Date: mm/dd/yyyy"
exit 1
}

FDATE="$1"
OLDIFS="$IFS"
IFS="/"
set $1
IFS="$OLDIFS"

get these errors...
spell_date: line 13: unexpected EOF while looking for matching `"'
spell_date: line 14: syntax error: unexpected end of file

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