Not sure if this is the correct forum, It not pls point me to the correct one.

I need an explanation of this regular expression:
grep /^[^\#]*sa2/

Noting the following:
If the ^ character is placed at the start of an expression, it matches at the beginning of the string. If placed after an open-square-bracket, [, it means 'not the contents of the square-brackets'. Otherwise it just matches '^'.
and this:
The * character matches zero or more of the preceding character or group.

Does not the above regex say: the statement is true if there are no # character at the beginning of the "line" (the # character somewhere else in the line does not matter) and the string: sa2 can be anywhere within the line irregardless of preceding or trailing characters. The string sa2 does not have to be at the beginning of the line?

Thanks..