Addition with the prefixing zeros included

sivasenthil_k · #1 (**permalink**) 09-26-2006

Hi

I need to do an add function but it should include the prefixed zeros

For Example
i=00123
j=`expr $i + 1`

The output it shows is 124 but I want the output to be 00124

Could any one help me finding out how to do this

Thanks

pressy · #2 (**permalink**) 09-26-2006

hi,

i moved your post from "news, links, events announcements" to "UNIX for Dummies Questions & Answers" and closed the poll.

and, here is your answer:

Code:

root@mp-wst01 # i=00123
root@mp-wst01 # j=`printf %05d $(expr $i + 1)`
root@mp-wst01 # echo $j
00124

regards pressy

sivasenthil_k · #3 (**permalink**) 09-26-2006

Hi

Thanks

I posted in the wrong group by mistake , Sorry about that

Regarding my query

I don't know what would be the length of the input string , actually 00123 would be the input from the user .The script would look like

read i
j=`printf %05d $(expr $i + 1)`
echo $j

The user can input 00123 or 0123 or 00000123 for which I want the output to be 00124 , 0124 , 00000124 respectively

Siva

sivasenthil_k · #4 (**permalink**) 09-27-2006

Hi

I have put some simple logic in place to do the trick for me , the code now looks like

read variable
length=${#variable}
y=`expr $variable + 1`
length1=${#y}
if [ $length1 != $length ]
then
t=`expr $length - $length1`
i=1
ttt=$y
while [ $i -le $t ]
do
i=`expr $i + 1`
ttt=`echo "0$ttt"`
done
echo $ttt
else
echo $y
fi

Sample outputs are
$ ./ttt
9
10
$ ./ttt
99
100
$ ./ttt
1
2
$ ./ttt
100
101
$ ./ttt
01
02
$ ./ttt
00101
00102
$ ./ttt
009
010
$

However I still feel there could be some simple logic to do the same , any suggestions please ??

Thanks
SIva

tayyabq8 · #5 (**permalink**) 09-27-2006

What about this:

Code:

read variable
zeros=`echo $variable | sed 's/\(0*\)[1-9]*/\1/'`
y=`expr $variable + 1`
print $zeros$y

Regards,
Tayyab

Ygor · #6 (**permalink**) 09-27-2006

That doesn't work. Here $ represents the ksh prompt...

Code:

$ set -x
$ read variable
+ read variable
001007
$ zeros=`echo $variable | sed 's/\(0*\)[1-9]*/\1/'`
+ echo 001007
+ sed s/\(0*\)[1-9]*/\1/
+ zeros=00007
$ y=`expr $variable + 1`
+ expr 001007 + 1
+ y=1008
$ print $zeros$y
+ print 000071008
000071008

Try this instead...

Code:

echo $variable | awk '{printf "%0*d\n",length,$1+1}'

Or...

Code:

printf "%0${#variable}d\n" $(expr $variable + 1)

reborg · #7 (**permalink**) 09-27-2006

I have closed the poll on this thread becasue it serves no useful purpose.

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