10 2 1 2 3 4 5 6 7 8

20 3 2 1 3 2 9 8 2 1

Need the data to be arranged:

10 2 1 5
2 6
3 7
4 8

20 3 2 1
1 2
3 8
2 9

please help!

For first line you can use the following
for second data arrangement you can use the above way

My datafile has about 50 lines how can go about to create a while loop to read datafile and diplace them as shown?

Thank you much!

First of all it sounds like a homework.

Secondly your input is not clear, you should post at least 5 lines of your input file and their required output to get the exact logic of what you want, as per your given 2 lines what I understand is that, if line no. is odd then take frist 3 columns, leave next 3 columns and print a single column then print one incremented column (4th col ) and print next column after leaving 3 columns, if line no. is even then reverse the order, take first 3 cols and last column, then take the 4th column and 2nd last, then 5th and 3rd last and so on.

Here is the code as per above logic: Which will yeild your desired output: Regards,
Tayyab

Thanks I will try!

It works great! thank you much! By the way it is not homework problem. I learn Unix from book and this wesite. I am great thanked every who had help me with all my asks!!!

Regarding this data arrangement post, I have other questions:

This is my datafile:

33 ;1 ;2 ;2 ;1 ;3 ;3 ;1 ;3 ; ; ; ; ;2 ;1 ;1 ;2 ; ; ;2 ; ; ;
111;1 ;2 ;2 ;1 ;3 ;3 ;3 ;3 ; ; ; ; ;2 ;1 ;1 ;2 ;4 ;4 ;4 ;4 ; ;

it is seperated by a ";" .


The code:


#! /bin/ksh
cnt=1
while read a b c d e f g h i j k l m n o p q r s t u v w; do
if [[ $cnt%2 -eq 1 ]]; then
echo $a
echo $b $n
echo $c $o
echo $d $p
echo $e $q
echo $f $r
echo $g $s
echo $h $t
echo $i $u
echo $j $v
echo $k $w
echo $l
echo $m
else
echo $a
echo $b $n
echo $c $o
echo $d $p
echo $e $q
echo $f $r
echo $g $s
echo $h $t
echo $i $u
echo $j $v
echo $k $w
echo $l
echo $m
fi
(( cnt=cnt+1 ))
done < datafile


The resuslts:

33
;1 ;2
;2 ;1
;2 ;1
;1 ;2
;3 ;4
;3 ;4
;1 ;4
;3 ;4
; ;
; ;
;
;
111;1
;2 ;1
;2 ;1
;1 ;2
;3 ;4
;3 ;4
;3 ;4
;3 ;4
; ;
; ;
;
;
;2


The data result are not correct since it printed the 350;1 as a single column.

I want:

33
;1 ;2
;2 ;1
;2 ;1
;1 ;2
;3 ;
;3 ;
;1 ;2
;3 ;
; ;
; ;
;
;

111
;1
;2 ;1
;2 ;1
;1 ;2
;3 ;4
;3 ;4
;3 ;4
;3 ;4
;;
;;

Please help!

Try to put IFS=";" before loop runs, if you find it difficult search these forums for IFS(Internal Field Separator), its ksh builtin.