Hi, I am trying to write a script that will send an email to me if the size of a folder is below a certain amount.

Does anyone know how to write the if (size < 1000) statement. I know how to send the email? I just need the code for determing a folder size.

Thanks,
Eric

Hi,

Try this:

#!/bin/sh

SIZE=`ls -ltr FILENAME|awk '{print $5}'`

if [ $SIZE -ge 700 ] ##say..size exceeds 700

then

echo "FILE SIZE EXCEEDED!!"

else

echo "FILE SIZE OK"

fi


## Hope this helps,

## Praveen Indramohan
~

@praveen : i think u got it a bit wrong.he said he wanted to be informed by an email...

the following code will work(hoping u have a mailing client installed in ur OS)
hope this works.....

yeah, may be,

but he said : "I just need the code for determing a folder size."

and he said : i know how to send email?( why the question mark?)

Anyway, hope it works for him.

Thanks,

Praveen Indramohan

Hi, I am using exact code from sayonm. I get the error though that:

line 2: }: command not found
line 3: [: -le: unary command expected

Anyone know how to fix these two errors. I am assuming by unary it just means to use <, >, =, etc.

As for the first error, it seems like it doesn't know the print command. I am using Ubuntu, if that helps.

Thanks,
Eric

please,
try this SIZE calculation, it does not need awk and removes those backticks.
advantage 2, you can define the directory as cmd line argument else the current directore is counted.
btw: do not forget to chmod +x the script !

SIZE=$( du -s $1 | expand | cut -d\ -f1 ) # note cut -d\<space><space> !!!