Problem in division

rochitsharma · #1 (**permalink**) 08-10-2006

hi
I am having two variables namely a=7 & b=8. I have to subtract these two variables. I am using the command

c=`expr $a / $b`

When I check the value of c, it comes out to be zero.
Please help.
Regards
Rochit

tmarikle · #2 (**permalink**) 08-10-2006

According to the MAN page:

Code:

     expr { \*, /, %} expr
           Multiplication,  division,   or   remainder   of   the
           integer-valued arguments.

what would you expect? Your answer will be zero. To get the remainder use the percent sign.

You can use awk:

Code:

 nawk 'BEGIN {print 7/8}'

vgersh99 · #3 (**permalink**) 08-10-2006

Code:

quoting 'man expr':
     expr1 {*, /, %} expr2
             Return the results of multiplication, integer division, or
             remainder of integer-valued arguments.

Code:

a=7
b=8
echo "scale=2; $a / $b" | bc

rochitsharma · #4 (**permalink**) 08-10-2006

Dear tmarikle & vgersh99,
Thanks alot both of you for helping. both solutions are working
But it will be very nice of you vgesh99 if u could explain me the command
bc

Regards
Rochit

tmarikle · #5 (**permalink**) 08-10-2006

Code:

nawk -v val_a=$a -v val_b=$b 'BEGIN {print val_a / val_b}'

or

Code:

nawk 'BEGIN {print '$a' / '$b'}'

rochitsharma · #6 (**permalink**) 08-10-2006

hi tmarkle
could u explain me your code

nawk -v val_a=$a -v val_b=$b 'BEGIN {print val_a / val_b}'

Thanks alot
Regards
Rochit

vgersh99 · #7 (**permalink**) 08-10-2006

Quote:

Originally Posted by rochitsharma

Dear tmarikle & vgersh99,
Thanks alot both of you for helping. both solutions are working
But it will be very nice of you vgesh99 if u could explain me the command
bc

Regards
Rochit

take a quick look at 'man bc' - it should be self-explanatory.

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