Striping process variable - UNIX for Dummies Questions & Answers

new9021 · #1 05-08-2006

Hello. I would like to strip out the process name from the ${0##*\} variable. So that if I have a script named "mytest.script" the variable would be populated with just "mytest" I have tried doing a substring but it doesnt seem to work.

Code:

name=`expr match "${0}" : './*\(/*.\)'`

Doing this gets me "m". I can do it in 2 steps. But I would like to accomplish in 1 if there is a way.

Thank you,

new9021 · #2 05-08-2006

Got a little bit closer with

Code:

name=`${0%.*}`

gives me "./my" but now it has the "./" that I want to get rid of.

help...

ranj@chn · #3 05-08-2006

Tried using 'basename' if that is your requirement.
basename /home/user1/new.sh .sh --> gives o/p as new.

new9021 · #4 05-09-2006

No I would like to use the ${0} variable to derive the name with out the extension. So if I had a script named thescript.script and i have a variable within the script:

Code:

name=${0##*/}

here i get "thescript.script"
however I want to get "thescript"

ranj@chn · #5 05-09-2006

after you get the thescript.script into 'name'. Do
fname=${name%%.script}
echo $fname --> gives 'thescript'

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