Hi all.,

i am using the follwowing command..
ls -ltr TNT.*.*.*.ctl* | awk -F" " '{print $6" "$7 }'

the output is:
Feb 27
Feb 27
Feb 27
Feb 27
Feb 28
Feb 28
Mar 9
Mar 21
Mar 21

from this output i am trying to get the FIND the files on march 21. i am using the find command no results.

can anyone please give me some suggestions

thanks
pavi

Show how you are using the "find" command. Your output cannot be used in the find command since the "Mar 21" string is not stored anywhere in this format.

Now that I think of it, this is probably what you are attempting to do:

Hello.,

i am trying to accomplish is;

i have a dir and inside that i have certain files. files keep arriving in that dir. the dir has lot of files but i have to process only those files that arrive today.

for eg: today is mar 21 so i have to process only those files that arrived today.

each dir comes with a prefix TNT and suffix as ctl*
so i tried to use this command;
ls -ltr TNT.*.*.*.ctl* | awk -F" " '{print $6" "$7 }'
the output is:
Feb 27
Feb 27
Feb 27
Feb 27
Feb 28
Feb 28
Mar 9
Mar 21
Mar 21

now i know that today ( Mar 21) there are 2 files that arrived. so i have to pick up ( or find ) these 2 files that arrived today and process them.

thanks
pavi

Hello.,


find INFOSCAN.*.*.*.ctl* -exec ls -ltr {} \; | grep "Mar 21"

the above command is working. but can nayone suggets me isntead of hard coding "Mar 21 " how can i get all the files for today's date.

thanks
pavi

Find gives you this already, there isn't any need to "ls" and "awk".

Try this:

find . -name TNT.*.*.*.ctl* -mtime 1

This will look for all new files matching your spec modified today.

Hello tmarikle

thanks man..your suggestion did wonders for me..

thanks a lot buddy..

have a nice day !!!