Using grep - UNIX for Dummies Questions & Answers

m223464 · #1 03-03-2006

I have a command (see below) which displays the name of any file containing the specified search string:

Code:

# grep -i -s -l "SIGILL" /var/mqm/errors/*.FDC
/var/mqm/errors/AMQ43618.0.FDC
#

How can this command be adapted so it displays the file's date stamp, i.e. as if I'm performing an ls -l on the resultant filename.

Code:

e.g.
-rw-r--r--   1 mqm      mqm           10577 Feb 25 04:34 /var/mqm/errors/AMQ43618.0.FDC

regards

Gareth

gauravgoel · #2 03-03-2006

edited as the response I gave was not correct

gauravgoel · #3 03-03-2006

ok got it, do it in a single step

Quote:

ls -lrt `grep -i -s -l "SIGILL" /var/mqm/errors/*.FDC`

Gaurav

vino · #4 03-03-2006

Quote:

Originally Posted by m223464

Code:

# grep -i -s -l "SIGILL" /var/mqm/errors/*.FDC
/var/mqm/errors/AMQ43618.0.FDC
#

This should work, I think.

Code:

grep -i -s -l "SIGILL" /var/mqm/errors/*.FDC | xargs ls -l

m223464 · #5 03-03-2006

Both these worked.

many thanks

Gareth

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