foreach loop question

clipski · #1 (**permalink**) 12-21-2005

Hello, I am new at this forum so please bare with me on this.

Within a given directory, I have a list of files in which in each file, I would like to do a substitution. I would like to substitute the string mlcl to mll in each file using the foreach command. I dont quite get how to do that. If you can provide help, it would surely be appreciated

jim mcnamara · #2 (**permalink**) 12-21-2005

Are you talking about perl?

clipski · #3 (**permalink**) 12-21-2005

I am in the Unix environment at a directory and thought to do something like

set x = `ls`
foreach i ($x)
`sed s/mlcl/mll/g`
end

but this doesnt seem to work

zazzybob · #4 (**permalink**) 12-21-2005

Do you want to move the files too (this is sh/ksh/bash)?

Code:

$ touch mlcl_1 mlcl_2 mlcl_3
$ ls mlcl_*
mlcl_1  mlcl_2  mlcl_3
$ ls | while read file; do
>   mv $file `echo "${file}" | sed 's/mlcl/mll/'`
> done
$ ls
mll_1  mll_2  mll_3
$

Cheers
ZB

clipski · #5 (**permalink**) 12-21-2005

I want to keep the change in the same file name, so I think
that I just dont need to do the file name touches and the mv
command. Is that corret Zazzy?

zazzybob · #6 (**permalink**) 12-21-2005

My above post was an interactive session, hence the "touch"es.

If you don't want to keep the changes, you can easily do (as long as there aren't a load of files....)

Code:

ls *mlcl* | sed 's/mlcl/mll/g'

Else; just do

Code:

ls | while read file; do
  echo "${file}" | sed 's/mlcl/mll/'
done

If you want to keep the filename change, just add in the mv.

Cheers
ZB

mahendramahendr · #7 (**permalink**) 12-22-2005

why you have put sed command in ` quotes ?? i guess it is not required

foreach i ( * )
sed s/mlcl/mll/g
end

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