question? - UNIX for Dummies Questions & Answers

brentdeback · #1 11-19-2005

Is there any way to use sed and count the number of alphabetic characters in a sentence?

Ygor · #2 11-20-2005

Is this homework?

matrixmadhan · #3 11-20-2005

try this,

not thoroughly tested,

Code:

# !/usr/bin/ksh

word="count of no of characters"
cnt=0
curr=""
match=""

while :
do
match=$match"."
if [ curr = `echo $word  | sed -e "s/$match//"` ] 2>/dev/null
then
break;
fi
cnt=$(($cnt + 1))
done
cnt=$(($cnt + 1))

echo "word count: $cnt"
exit 0

vgersh99 · #4 11-20-2005

Code:

echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c

matrixmadhan · #5 11-21-2005

Quote:

Originally Posted by vgersh99

Code:

echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c

the above cnt would include the terminating character also

Code:

count=$((`echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c` - 1))
echo $count

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