How can I match . (actual dot) using sed?

jingi1234 · #1 (**permalink**) 09-19-2005

Hi All,
How can I match . (actual dot) using sed? Please help.

Thanks

vino · #2 (**permalink**) 09-19-2005

You need to escape it with a \

Look at this.

Code:

sh-2.05b$ cat jing.txt
test
.
test.match

Code:

sh-2.05b$ sed -n -e '/\./p' jing.txt
.
test.match

jingi1234 · #3 (**permalink**) 09-19-2005

Thanks vino.

But this doesn't work. I am looking for /./* (one or more of /./ and replace with a single /./

I tried dereferencing . and /
it doen't work. Please help.

Thanks

vino · #4 (**permalink**) 09-19-2005

This is going to be a confusing regex.

Code:

sed -e 's#\/\.\/\{1,\}#\/\.\/#g'

vino

jingi1234 · #5 (**permalink**) 09-19-2005

Please see below:

cat 1 gives:

/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

sed -e 's#\.\{1,\}#\.#g' 1 > 2

now see cat 2

/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

It is not working.

vino · #6 (**permalink**) 09-19-2005

Yes the previous solution will not work.

But this should work

Code:

sh-2.05b$ cat jing.txt 
test
/./
test/.//.//./match
sh-2.05b$ sed  -e 's#\(\/\.\/\)*#\1#g' jing.txt 
test
/./
test/./match

vino

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