How to exclude files from printed results

umen · #1 (**permalink**) 09-18-2005

Hello
I have application that part of its command I can get list of files to the stout . with the path .
like :
./blah/blah/foo.c
./blah11/blah11/foo11.c
./blah12/blah12/foo11.h

now I will like to filter this result and for instance see the "*.h" file or the "*.c" file or only the files that starts with foo
Thanks

stolz · #2 (**permalink**) 09-18-2005

if you pipe to grep -v what you dont want you will get the desired effect.

ie if you didnt want to see files called foo.c you would grep -v foo.c and get the following output:

./blah11/blah11/foo11.c
./blah12/blah12/foo11.h

zazzybob · #3 (**permalink**) 09-18-2005

But if you wanted files that start with foo, can contain anything else, and end in .c or .h, then use a regular expression to grab what you want.

e.g.

Code:

my_command_that_produces_some_output | grep "/foo.*\.[ch]$"

Either way, grep is what you want.

Cheers
ZB

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