Using printf in bash

lavender · #1 01-03-2013

Code:

printf "%5.5\n" "1234567890"

Yoda · #2 01-03-2013

Code:

num="1234567890"
printf "%d\n" ${num: -5}

RudiC · #3 01-04-2013

This works for numbers. Use %s format specifier for characters:

Code:

$ var="ABCDEFGHIJK"
$ printf "%5s\n" ${var:5}
FGHIJK
or
$ printf "%5s\n" ${var: -3}
  IJK

lavender · #4 01-04-2013

Thanks!

Scrutinizer · #5 01-04-2013

Code:

num="1234567890"
echo "${num#?????}"

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