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#1
12-06-2012
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Displaying field of NR, not the line #
Within AWK, how do you display a field of NR? Here's my code: Code:
awk '(NR>1) && (P1=$1-w)>=100000 {print "increase of" " " P1*.0000179," " "kW at" " " 'NR*60/431900' " " "minutes" "\n" "change from" " " 'NR-10($1)' " " "kW to" " " 'NR+70($1)' "\n"}{w=$1}' filenameI can change NR and print line #'s, but cannot get a field to print...the error comes at the segment Code:
'NR-10($1)' " " "kW to" " " 'NR+70($1)' |
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#2
12-07-2012
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Quote:
 )You can directly use NR. |
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#3
12-07-2012
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Quote:
Code:
awk '(NR>1) && (P1=$1-w)>=100000 {print "increase of " P1*.0000179 " kW at " NR*60/431900 " minutes\nchange from " NR-10($1) " kW to " NR+70($1) "\n"}{w=$1}' filenameWhich after throwing away the strings from the print statement, leaves 4 expressions to be evaluated and printed: P1*.0000179 , NR*60/431900 , NR-10($1) , and NR+70($1) . The first two of these are valid expressions in awk; the last two are not. What were you expecting those expressions to do? Without having a sample of your input file, an example of the output you expect to produce, and a description of what you're trying to do; there isn't any way that we can help correct your code. |
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#4
12-07-2012
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To answer your question directly, $ is the 'column' operator in awk.
$(1+1) gets you column 2. $VARIABLE gets you the column number given by the variable. So, $NR. |
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