listing based on user.

I have files in some folder that come from many user

-rwxrwxr-x  1 ratih     pbank 4827112 Jun  8 08:37 S92TA-8.sgy
-rwxrwxr-x  1 ratih     pbank 4724568 Jun  8 08:37 S92TA-6.sgy
-rwxrwxr-x  1 ratih     pbank 4929656 Jun  8 08:37 S92TA-19.sgy
-rwxrwxr-x  1 ratih     pbank 9820216 Jun  8 08:37 S92TA-5.sgy
-rwxrwxr-x  1 ratih     pbank 4929656 Jun  8 08:37 S92TA-17.sgy
-rwxrwxr-x  1 ratih     pbank 6286392 Jun  8 08:37 S92TA-1.sgy
-rwxrwxr-x  1 ratih     pbank 4827112 Jun  8 08:37 S92TA-10.sgy
-rwxr-xr-x  1 aiprawira pbank 6106640 Jun 26 08:50 S92JA-002.sgy
-rw-r--r--  1 aiprawira pbank 1240080 Aug 30 10:11 S74JA-009.sgy
-rwxrwxr-x  1 aliyyus   pbank 1531440 Sep 12 09:29 S78JA-018_1.SGY
-rwxrwxr-x  1 aliyyus   pbank 2295360 Sep 12 09:29 S78JA-016.SGY
-rwxrwxr-x  1 aliyyus   pbank 2006768 Sep 12 09:29 S78JA-014_1.SGY
-rwxrwxr-x  1 aliyyus   pbank 1514464 Sep 12 09:29 S78JA-018_2.SGY

simply using grep with ls, or more tricky using the command find...
With grep precedance is important (is it date or user most important?) but since you want 2 conditions hte importance is less except for performance... (like in sql language...)

You could try to see:

ls -l |grep <date> | grep <user>

Try like...

 ls -ltr| awk '{if($3=="ratih") print}'

what if I want to make a list from a range of time. like listing the files from june-august??

There are several possibilities depending on what you want included in the list. Several of them are much easier to implement if you have the desired start time and end time as timestamps on existing files. For a June to August search, create the following files:

touch -t 201205312359.59 __start__
touch -t 201209010000 __end__

find <directory_list> -newer __start__ ! -newer __old__