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#1
09-21-2012
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Du -sk command in SunOS 5.10
Hi, I am little confuse after using Code:
du -sk on file . I have file listing like: Code:
-rw-r--r-- 1 Xuser Ygrp 51419029531 Sep 21 07:40 catalina.out when i issue cmd : Code:
du -sk catalina.out gives output as Code:
1804511 catalina.out This means 1804511 KB. Which means 1 GB. But if i calculate using 51419029531 bytes / 1024 bytes = 50213896.0 KB 50213896.0/1024=49037 MB 49037/1024= 47 GB It shows 47 GB but du shows 1 GB. Please let me know where I am doing wrong. Thanks Krsna
Last edited by vbe; 09-21-2012 at 03:47 AM.. |
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#2
09-21-2012
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try this also... Code:
stat -c%s catalina.out ls -lh catalina.out du -h catalina.out |
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#3
09-21-2012
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You will have to explain how you got your first figure... Look: Code:
slo4:/export/home/vbe $ uname -r 5.10 slo4:/export/home/vbe $ ls -l amanda-3.3.0.tar.gz -rwxr-xr-x 1 vbe sysadm 4193702 Nov 7 2011 amanda-3.3.0.tar.gz slo4:/export/home/vbe $ du -sk amanda-3.3.0.tar.gz 4100 amanda-3.3.0.tar.gz |
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#4
09-21-2012
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Might be a "sparse file", i.e. a file with holes in it. List it with
ls -s , col 1 will show the actually used blocks on disk, as does
du , col 5 will show what the file system thinks the size is: Code:
$ ls -ls fn 8 -rw-r--r-- 1 root root 4194339 Sep 21 09:56 fn $ du -sk fn 8 fn |
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