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hi mate,
Thanks for the reply. I'm sorry I've been so vague with every question I've asked but I've kind of been set a 'Linux Challenge', and although I'm allowed to ask for help, I can't be incredibly specific (which is frustrating the hell outta me.). Apparently, StartX has been disabled, so my situation is this. A Linux environment (using a C-shell.) has been completely tailored for me to solve a challenge. I'm not allowed to use any scripts, I have no permissions on practically everything as I'm supposed to use my observation skills to determine my goal. Now here's my problem. Whenever I type "echo" with anything after it, it will ALWAYS output: $input So even if I try "echo 'Hi, how are you?'", it would always output: $input. I'm pretty certain that my goal lies within this variable, but it won't let me print the damn thing. I've tried cat $input, print $input, print($input), but nothing happens (most commands have been disabled too to be incredibly restrictive.) Is there a way to display the contents of a variable, without the use of any scripting, and without the cat/print commands? Thanks guys, sorry to harp on about this. hellz. |
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hi mate
![]() I've run "which echo" but it comes up with nothing. It's just a simulation, there are no marks for this or anything like that. It's more of a "test project" to see if linux newbies (not computer newbies.) are able to investigate and find holes in systems by doing their own research. I mean with regards to Linux, I really don't know anything, and most of the things I've read up on have been disabled which is why I've resulted to asking questions in here in the hope I can find something. I totally apologise if this is the wrong place to post in but I just can't find anywhere else that will help. Thanks again ![]() hellz. |
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