if command -problem

vasikaran · #1 (**permalink**) 06-27-2005

Hi,

This is Vasikaran, I am just trying to run the if command using this test program, but while running , i am getting the syntax error as

"syntax error: unexpected end of file"

this is the test program
******************

echo " enter number"
read num
echo "Enter the choice of you want to see "
echo "1. 1message"
echo "2. 2message"
echo "3. 3message"
read choice
if (choice=1) then
echo "This is reading the first choice"
endif

Pls note : i am running this program in linux environment

Thanks for the help in advance.

Vasikaran

google · #2 (**permalink**) 06-27-2005

Change the "if" line to this: Note there the spaces after the "[" and before the "]" are required. Also, to access the value of a variable in shell, prefix the variable with a "$" sign. Use "fi" to close the "if" statement.

Code:

if [ $choice -eq 1 ] then
echo "This is reading the first choice"
fi

You can clean up your code by using a "select case" which will build the menu for you. Here is the syntax (note that the ";;" must end every case.)

Code:

select NUM in 1 2 3 quit
do
   case $NUM in
      1)  echo "This is reading the first choice"
           ;;
      2)  echo "This is reading the second choice"
           ;;
      3)  echo "This is reading the third choice"
           ;;
    quit) echo "Goodbye"
           exit;;
   esac
done

Lastly, to fancy it up a bit, use the builtin variable PS3 to set your prompt string for the menu (Add it just before the "select case" statement)

Code:

PS3="Make a Selection From the Following List"

rahul123_libra · #3 (**permalink**) 06-27-2005

yes use spaces between [ and ]

u can also use

if
....
....
...
fi

vasikaran · #4 (**permalink**) 06-27-2005

Thanks for the reply..

I have tried using if .........fi command but while trying i am getting this below mentioned error.. pls help

Ofcourse case statement is working, but i want to work it out with If statement..

"syntax error near unexpected token `fi'
search1.sh: line 16: `fi'"

Thanks and Regards
Vasikaran

rahul123_libra · #5 (**permalink**) 06-27-2005

Can u plz paste the code of the if block

reborg · #6 (**permalink**) 06-27-2005

Neither of the suggestions will work for the OP as he is using a csh base shell. I'm pretty rusty on csh but I think it should be something like

Code:

echo " enter number"
read num
echo "Enter the choice of you want to see "
echo "1. 1message"
echo "2. 2message"
echo "3. 3message"
read choice
if ( $choice == 1 ) then
    echo "This is reading the first choice"
endif

vasikaran · #7 (**permalink**) 06-28-2005

Actually i am trying the following code when in run this program in linux environment

echo " enter the mobile number "
read mob
echo "Enter the choice of log you want to see "
echo "1. F.log"
echo "2. A.log"
echo "3. I.log"
echo "4. R.log"
echo "5. M.log"
echo "6. A.log"
read choice
if [ $choice == 1 ] then
echo "This will give the contents present in f.log"
grep $mob /data/logs/f.log | cut -f1,2,4,5,11 -d" "
endif

the error message i am getting as

"line 17: syntax error: unexpected end of file"

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
problem in awk command	viveksnv	Shell Programming and Scripting	3	03-03-2008 04:59 AM
problem with tr command	ravi raj kumar	UNIX for Advanced & Expert Users	2	07-02-2007 06:41 AM
problem with dd command or maybe AFS problem	Anta	Shell Programming and Scripting	0	08-25-2006 10:10 AM
ls command problem	buckhtr77	SUN Solaris	2	12-06-2005 04:16 PM
Problem while using Sed command	gopskrish	UNIX for Dummies Questions & Answers	2	06-27-2005 11:26 AM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode	Rate This Thread: