group by in files :-) - UNIX for Dummies Questions & Answers

hellsd · #1 (**permalink**) 06-21-2005

My file looks like:

X^~^12^d
X^~^19^d
Y^~^5^d
Y^~^10^d
Y^~^11^d
Z^~^14^d

I need a script that will "group by" the first field and Concatenate the values.

My output should be:

X^~^12,19^d
Y^~^5,10,11^d
Z^~^14~d

Does anyone have any idea ?

vino · #2 (**permalink**) 06-21-2005

Your post is on similiar lines to that of

shell script comparing files in a file

Check it out.

vino

hellsd · #3 (**permalink**) 06-21-2005

where the delimiter is ^ and if the concatenated field is not last.

Any idea ?

vgersh99 · #4 (**permalink**) 06-21-2005

something to start with:

nawk -f hell.awk file.txt

hell.awk:

Code:

BEGIN { FS=OFS="^" }
{
    arr[$1] = ($1 in arr) ? arr[$1] "," $3 : $3
}
END {
  for (i in arr)
    print i OFS "~", arr[i]
}

hellsd · #5 (**permalink**) 06-21-2005

you are the best

vgersh99 · #6 (**permalink**) 06-21-2005

Quote:

Originally Posted by hellsd

you are the best

take a number....
glad to be of help.

hellsd · #7 (**permalink**) 06-21-2005

Lets say the input file is:
ABC^1^~^data^x
ABC^2^~^data^x
ABC^3^~^data^x
DEF^4^~^data^y
DEF^4^~^data^z
DEF^5^~^data^y
DEF^5^~^data^z
DEF^6^~^data^z
DEF^6^~^data^y
XYZ^7^~^data^t

Now I would like to group couple of fields(field 2 and field 5)
My output should be:

ABC^1,2,3^~^data^x
DEF^4,5,6^~^data^y,z
XYZ^7^~^data^t

Notice that I would like to print all the line's fields.

Is it possible?

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