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#1
07-06-2012
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print line that matches and next line, too
I'm using sh on hp-ux and want to find / print a line that matches 132.101- and the next line, too. grep -A isn't supported on hp-ux, so I'm trying awk and sed. The code below works but only prints the first occurence. I need all matches from the file. Code:
awk '/132.101-/{f=2;print;next}f{print;exit}' INFILE1 >outfile1I've also tried sed but this cannot be parsed, my shell tells me. Code:
sed -n -e '/132.101-/{N;p}' INFILE1 >outfile1Thanks for your help! |
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#2
07-06-2012
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Code:
awk '/132\.101-/{print;getline;print}' INFILE1 > outfile1Following are the issues with your awk: Code:
awk '/132.101-/{f=2;print;next}f{print;exit}' INFILE1 >outfile11) The regex is not correct (although it will work). . is a regex metacharacter which matches any character. So, to match a literal . , you'll need to escape the period. 2) The exit statement will make awk stop after it has printed out the first line after the one containing "132.101-". Hence, you are getting only 2 lines. If you want to use your awk, you'll need to modify it a bit: Code:
awk '/132.101-/{f=2;print;next}f{print;f=0}' INFILE1 >outfile1Last edited by elixir_sinari; 07-06-2012 at 05:23 PM.. |
| The Following User Says Thank You to elixir_sinari For This Useful Post: | ||
Scottie1954 (07-06-2012) | ||
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#3
07-06-2012
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That worked! Thanks a bunch. Never thought that adding something straightforward like ;getline; would be parsed by hp-ux. I also changed my pattern a bit to find another potential match: Code:
awk '/132\.10[1-2]-/{print;getline;print}' INFILE1 >outfile1---------- Post updated at 04:16 PM ---------- Previous update was at 02:25 PM ---------- Just for argument's sake, how would I do the opposite -- pull the line matching the pattern and the previous line? Thanks. ---------- Post updated at 04:42 PM ---------- Previous update was at 04:16 PM ---------- I found an answer after some more digging: Code:
awk '/132\.101-/{print x;print};{x=$0}' INFILE1 >outfile1 |
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