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#1
07-05-2012
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Display blocks containing specific pattern
Hi, I have a file containing multiple entries. Each block starts with <BEGIN and ends with <END. Sample data is given below Code:
<BEGIN
IMSI=095001202630;
MSISDN=00145132916;
DEFCALL=TS11;
CURRENTNAM=BOTH;
CAT=COMMON;
TBS=TS11&TS12&TS21&TS22;
CARDTYPE=SIM;
VLRLIST=200;
CLIPOC=NO;
LCS=1;
OCSI=131;
TCSI=88;
UCSI=28;
SUBRES=ALLPLMN;
SUB_AGE=0;
UPL_TIME=1340536017;
GPRSUPL_TIME=1339578803;
CHARGE_GLOBAL=NONE;
<END
<BEGIN
IMSI=095001202630;
MSISDN=00145132916;
DEFCALL=TS11;
CURRENTNAM=BOTH;
CAT=COMMON;
TBS=TS11&TS12&TS21&TS22;
CARDTYPE=SIM;
VLRLIST=200;
CLIPOC=NO;
LCS=1;
OCSI=131;
SUBRES=ALLPLMN;
SUB_AGE=0;
UPL_TIME=1340536017;
GPRSUPL_TIME=1339578803;
CHARGE_GLOBAL=NONE;
<ENDI want to display all lines b/w <BEGIN and <END if OCSI=131 and TCSI= field is not present. In above data, result should be second block as OCSI is 131 and TCSI field is not present. I can get the all lines b/w BEGIN and END using sed but at loss on how to proceed further. Thanks Last edited by Scrutinizer; 07-05-2012 at 07:44 PM.. Reason: quote tags -> code tags |
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#2
07-06-2012
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Code:
sed -n '/<BEGIN/,/<END/{
H
/<END/{
s/.*//
x
/\n *TCSI=/! {
/\n *OCSI=131.\n/ {
s/^\n//
p
}
}
}
}' inputfile |
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#3
07-06-2012
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You can try this in gawk Code:
awk 'BEGIN {RS="<BEGIN"} $0 !~ /TCSI=/ && /OCSI=131/ { print RS $0 } ' |
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