Hi ,
I want to print the nth and n+1 lines from a file once it gets a pattern match.
For eg:

aaa
bbb
ccc
ddd
gh
jjjj

If I find a match for bbb then I need to print bbb as well as 3rd and 4th line from the match.. Please help..Is it possible to get a command using sed

much easier with awk:

awk '/bbb/ { print ; for(n=0; n<2; n++) { getline ; print } }' inputfile

Thanks a lot Corona688 ... But is it possible to get a command in sed ..
I tired the below one .. but looks like some issue is there with the command ..

sed -n '/bbb/,+2p' filename

Right tool for the right job and all that. Why sed? Is this homework?

No not home work I am learning sed commands ..

$ sed -n '/bbb/ {p;n;p;n;p;}' infile

Try this one

grep -A2 'bbb' inputfile