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#1
06-16-2012
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Problem with grep from pattern file with if
I have two sets of data accept.txt is the list of 50 words Code:
Tom Anne James ... and I have a file01.txt which has the frequency of words which I got it using Code:
cat main.file | tr -d '[:punct:]' | tr ' ' '\n' | tr 'A-Z' 'a-z' | sort | uniq -c | sort -n -r > file01.txt so my file now looks like this Code:
155 the 100 a 55 this 34 Anne 5 James I need the output to look like this Code:
0 34 5 I tried using grep but dont know how to replace things with 0 and just print one column Code:
for name in `cat accept.txt ` do grep $name file01.txt; done I have to do this for 20 files in the same folder and would like to eventually print it as
can someone please help me? Thank you in advance for your time |
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#2
06-17-2012
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Try this script: Code:
#!/bin/ksh
ls file* | sort | tr '\n' '\t' | sed 's/^/\t/g'
echo ""
for name in `cat accept.txt`
do
printf "${name}"
for i_file in `ls file* | sort`
do
count=`grep -c "${name}" "${i_file}"`
printf "\t${count}"
done
echo""
done |
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#3
09-03-2012
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Thanks for the help... I find a solution for if but yours look much more pro
 |
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