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#1
06-13-2012
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Need help with 2 similar commands with different outputs
NEVERMIND.... "$TIME" did the trick... stupid me.  Hi, I know that this must be something pretty dumb but I cant figure it out myself. I have this: Code:
#!/bin/bash TIME="Time: 20120611" FILE=file.log grep $TIME $FILE And I get the following output: Code:
file.log:Time: 20120611 file.log:Time: 20120611 file.log:Time: 20120611 . . . but when i run Code:
grep "Time: 20120611" file.log I get my expected output: Code:
Time: 20120611 Time: 20120611 Time: 20120611 . . . Why I get 2 different outputs when basically Im using the same command? Thanks in advance Last edited by RedSpyder; 06-13-2012 at 09:36 AM.. |
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#2
06-13-2012
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I guess (and it is just a guess, since I know next to nothing about how shell works) is that 1. Since the variable $FILE may refer to more than one files, grep is showing you the exact filename which matches content. 2. The variable TIME is not quoted in the grep command. Doesn't it show you a "no file or directory found" message? What is the output of: Code:
TIME="Time: 20120611";FILE=file.log; grep "$TIME" $FILE If it does not show you the file name in output, then my guess is that the part after "Time:" of the TIME variable is being treated as one of the search files and hence the output tells you the name of the file in which the data is found (as is the norm for multiple file grep). |
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#3
06-13-2012
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Yeah the problem is that I didnt used "" around $TIME. Put them and it worked.
Thanks! |
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