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#1
06-10-2012
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Double variable substitution
Code:
$ ABCel='abc@gmail.com' $ XYZel='xyz@gmail.com' $ MYel='my@yahoo.com' $ echo $ABCel abc@gmail.com $ echo $XYZel xyz@gmail.com $ echo $MYel my@yahoo.com I tried 3 variations, but not getting the expected result: Code:
$ for VAR in ABC XYZ; do echo -e "${VAR}el $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.comCode:
$ for VAR in ABC XYZ; do MAIL=${VAR}el; echo -e "$MAIL $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.comCode:
$ for VAR in ABC XYZ; do MAIL=${VAR}el; echo -e "${MAIL} $MYel"; done
ABCel my@yahoo.com
XYZel my@yahoo.comExpecting Result: --------------------- Code:
abc@gmail.com my@yahoo.com xyz@gmail.com my@yahoo.com What am I missing here? Thanks Last edited by Scrutinizer; 06-10-2012 at 02:55 PM.. Reason: code tags |
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#2
06-10-2012
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Try this:
eval echo \$${VAR}el
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| variable substituion |
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