Hi,
I have a long log file. Out of which I want to filter particular occurrences where APC=4-033-0.

Please help how it can be done.

Input :

+++ ELEMENT 12-05-27 23:15:06 CC 3482 #040185 >
 REPT APB TPE=C7NTL   SM=22  OPC=4-003-7   APC=4-033-4  inaccessible
 END OF REPORT #040185 ++-

+++ ELEMENT 12-05-27 23:15:56 CC 3482 #040187 >
 REPT APB TPE=C7NTL   SM=22  OPC=4-003-7   APC=4-033-0  inaccessible
 END OF REPORT #040187 ++-

+++ ELEMENT 12-05-27 23:16:26 CC 3482 #040188 >
 REPT APB TPE=C7NTL   SM=22  OPC=4-003-7   APC=4-033-6  inaccessible
 END OF REPORT #040188 ++-

OPC=4-003-7   APC=4-033-0  inaccessible 12-05-27 23:15:56

Based on the input given ..

$ nawk '/APC=4-033-0/{print $5,$6,$7,x};{x=$3" "$4}' infile
OPC=4-003-7 APC=4-033-0 inaccessible 12-05-27 23:15:56

Thanks!!! It works Fine..But getting blank lines in between output. How to suppress them.

Pipe output to

| sed '/^ *$/d'

Or pipe output to | grep '.'

Optimal method:

| awk NF

Originally Posted by vanand420 Thanks!!! It works Fine..But getting blank lines in between output. How to suppress them.

Thanks..executing the above code "| awk NF" resolved the case.