Hypothetically, suppose that

file1

id v1 v2 v3 v4 v5 v6 v7..........v100
1 1 1 1 1 1 2 2 .....50
2 1 1 1 1 1 2 2 .....50
3 1 1 1 1 1 2 2 .....50
4 1 1 1 1 1 2 2 .....50
5 1 1 1 1 1 2 2 .....50

Something like this maybe:

for (( i=0;i<20;i++ )) do awk '{OFS="\t"}NR!=1{{printf($1"\t")} for (j=1;j<=5;j++) {c=j+('$i'*5)+1; printf($c"\t")}{printf("\n")}}' file1 > file_$i; done;

Or:

awk '{for(i=2;i<=NF;i+=c){s=$1; f="chrom" (i-2)/c+1 ".txt"; for(j=0;j<c;j++)s=s OFS $(i+j); print s>f}}' OFS='\t' c=5 infile

Thanks!!! what a life saver.

I just need to modify little bit for my problem. I hope it works

---------- Post updated at 09:52 AM ---------- Previous update was at 09:40 AM ----------

jawsnnn,
Is there any way that I could keep my headers of each field?