Dear Members,

I have an variable by name dir.If i do echo $dir i will get the path (/usr/bin/).

I am writing a shell script which will prompt to enter the variable name if run.Suppose the script name is test.sh.

If run test.sh it will prompt for entering variable name which is dir.Suppose if i do echo $dir inside the shell script it is not giving me the path.looks like it passing the value entered as a literal string.

How can i get the actual value of variable dir inside the script.

Following is my code inside the shell script:

VariableName()
{
        echo "***************************************"
        echo -n "Please Enter Variable Name : "
        read Read_VariableName
}

VariableName
echo $Read_VariableName

Please post what Operating System and version you are running and what Shell you use.

If I guess that you have a Shell which creates a sub-shell for a function then variables become local to that function.
A common circumvention is:

EDIT: This script does not work! Ignore it.

VariableName()
{
        echo "***************************************"
        echo -n "Please Enter Variable Name : "
        read Read_VariableName
        echo "${Read_VariableName}"
}

VariableName | read Read_VariableName

echo "${Read_VariableName}"

I don't think that works in anything but ksh, since other shells will put the read in a subshell, too...

Another way to do so is a temporary file.

We are using Linux 2.6.9-78.0.13.0.1.ELsmp x86_64.

The shell is ksh.

Thanks
Sandeep

---------- Post updated at 10:19 PM ---------- Previous update was at 10:12 PM ----------

methyl,

I tried your method but it is not working. The result is the same as input.

If you have any other idea please let me know.

Thanks
Sandeep

Have a go with this:

Code:

#!/usr/bin/env ksh
function VariableName
{
        echo "***************************************" >&2
        printf "Please Enter Variable Name : " >&2
        read Read_VariableName
        echo "${Read_VariableName}"
}


VariableName | read Read_VariableName

echo "${Read_VariableName}"

Read_VariableName=$( VariableName )

WARNING! eval when used like this can be dangerous. See a few posts below for more info!

Are you trying to do something like this:

#!/bin/ksh

dir="/usr/bin"

VariableName()
{
        echo "***************************************"
        echo "Please Enter Variable Name : "
        read Read_VariableName
}

VariableName
eval echo \$$Read_VariableName


exit 0
$ x
***************************************
Please Enter Variable Name :
dir
/usr/bin
$

If the O/P has ksh as stated in a reply to one of the questions, the original script in post #1 should work. We need the O/P to check which Operating System and Shell is actually in use here.