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#1
02-03-2012
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Clarification required on sed
Hi
Can some one tell what does this sed command do sed 's/[]*[]$//g I am more curious on the highlighted part , can some one explain what does that mean. Thanks Sri |
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#2
02-03-2012
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The final $ is an anchor, means end of the line. That's easy. Now the outer brackets: Code:
[]*[] mean "match any one of these characters". E.g., if you have [abd], it will match any of the chars 'a', 'b', 'd'. So the whole thing will strip (substitute with empty string) any trailing ],[,or * on the line (only one character). 'g' is unnecessary, because of the $ anchor, you cannot substitute any further. And to make this syntactically correct, we need a closing single quote also. Here: Code:
$ echo 'sfj[dd]aa[][]*sd[667]qf[[]]*[]' | sed 's/[]*[]$//' sfj[dd]aa[][]*sd[667]qf[[]]*[ To strip all the trailing ],[, or *, you just an *, quantifier: Code:
$ echo 'sfj[dd]aa[][]*sd[667]qf[[]]*[]' | sed 's/[]*[]*$//' sfj[dd]aa[][]*sd[667]qf Last edited by mirni; 02-03-2012 at 03:41 AM.. Reason: added example |
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