I'm very new to Unix, so forgive me for what will probably be a very quick fix. I have the following in a ksh script. Its purpose is to return yesterday's date. The $DAY part is coming back with a '2' but I need it to return as '02'. How can I do that?


date '+%b %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0)
MONTH=12
YEAR=`expr "$YEAR" - 1`
;;
esac
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
esac
}

Something like this will strip the leading zero, but will leave dates beginning with 1,2 or 3 alone...

echo `date +%d` | sed 's/[0]\([0-9]\)/\1/'

Cheers
ZB

Where would I add that to this script?

You don't want to strip a leading zero anyway. You want to add a leading zero. Try this:

((DAY < 10)) && DAY="0"$DAY

Put it after the code that sets DAY.

Re-reading your OP, you want to ADD the leading zero on dates less than 10, correct?

If so add
Cheers
ZB