hi,

I have the following input in file:
abc
ab
a
AB
b
c
a
C
B
When I use uniq -u file,the out put file is:
abc
ab
AB
c
v
B
C
b

Unfortunately, the uniq is not able to ignore case.

How can I check the file in order my output file will be:
abc
v

Thanks, Roy.

convert into upper case or lower case and do sort ....


cat file1 | tr "[a-z]" "[A-Z]" | sort -u

Because then I will lose the real values in the original file and the data I will get will be like converted (from lower to upper or and vice versia), because the input in file can be for example: "RsdA" and it has meaning


I thought there is a special/smart uniq that can do it.
Does anyone know how to do it?
Anyway, Thanks.

-----------------------------------------
Posted by hellsd:

Because then I will lose the real values in the original file
-----------------------------------------------------------


We are not changing the data in original file ; o/p u can redirect to some other file.

file1 contain:
danIel
Kevin
DON
KEVIN
don

If I run your command as the following :
cat file1 | tr "[a-z]" "[A-Z]" | sort -u >outputFile
outPutFile contain:
DANIEL
DON
KEVIN

And this is not what I expect:
I need that the output will contain:
danIel

This is why I use uniq -u but it doesn't ignore case.

Thanks,

Roy.

I hope following small script will solve yr prblem ;


#!/usr/bin/ksh

cat file1 | tr "[A-Z]" "[a-z]" | sort | uniq -u > file2

while read line
do
grep -i $line file1
done < file2

Your script is great but it doesn't answer my question.

I need to keep the exact uniq content I have in the original file:
(suppose That each line has a pssword which is case sensetive)

So if my input file1 contain:
DAVID, aaBBCC
don, abcDk
kevin
KEVIN
DON, aBcDk

When I activate your script, I get:
david aabbcc
(line case was change)

And this is not what I need, I except to have the exact uniq content:
DAVID, aaBBCC

Again, thank you very much for your efforts and I hope that I will finally have a solution for it.

Roy