how do you print the lines that contain integers only, using grep or awk?

thanks ,
apalex

------------------
this file below:
qwerty
01234
asdfgh
01234
qwer12
asdf05

will be:
01234
01234
qwer12
asdf05

you could use awk to get only those records that are integers only as you asked. However your example, you include records that are alphanumeric

awk ' /[[:digit:]]/ { print $0 } ' your_file

you are right sorry about that.

how to awk, to print the lines with integers only, having random patterns.

from:

qwerty
12345
asdfg
56789
zxcvb
00001
58364
22222


will be:

12345
56789
00001
58364
22222

can this be done using the same command above?

thanks.
apalex

Try using grep...

grep -E '^[0-9]+$' file1

Yes. You can use the Awk command above to produce a list of entries composed of only integers.

awk ' /[[:digit:]]/ { print $0 } ' your_file

from:

qwerty
12345
asdfg
56789
zxcvb
00001
58364
22222


will be:

12345
56789
00001
58364
22222