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Regex in find command

 
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# 1  
Old 11-23-2010
Regex in find command
Hi,

I need to find out the files whcih contains date in YYYYMMDD in their name.

I don't know if I can use regex in side find.

Now I am using commad for the same purpose which is not full proof.

Code:
find . -name "*[0-9][0-9]*" -print

But I want then It should contain at lease 8 digit in their names.
I tried with
Code:
find . -name "*[0-9][0-9]{8}*" -print

but no luck. Any idea....

Thanks,
Siba S Nayak
Last edited by siba.s.nayak; 11-23-2010 at 08:23 AM..
# 2  
Old 11-23-2010
Try something like:
Code:
find -name "*[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]*"

This User Gave Thanks to Franklin52 For This Post:
siba.s.nayak
# 3  
Old 11-23-2010
Hi,
I would use sed
Code:
find . | sed -n '/[0-9]\{8\}/p'

ciman
Last edited by Scott; 11-23-2010 at 02:30 PM.. Reason: Code tags
# 4  
Old 11-23-2010
Just for completeness I think some versions of 'find' support extended/perl regexp. This works with GNU findutils:

Code:
find . -regextype posix-extended -regex '.*[0-9]{8}.*' -print

 
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