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#1
12-23-2009
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Proper Expression To Not Include A String...
I have a folder of scripts: Code:
bash:/folderpath/> ls beginFile.sh beginFileBackup.sh beginAnother.sh beginAnotherBackup.sh beginJunk.sh beginJunkBackup.sh I'd like to be able to call just one (beginFile.sh) using this type of scheme: Code:
#Run the beginFile script without the word "Backup" in it. echo /folderpath/beginFile[^Backup]*.sh | xargs -n1 sh #Run the rest of scripts with the exception of the beginFile.sh script. echo /folderpath/begin[^File[^Backup]]*.sh | xargs -n1 sh Also, what If I did it this way: I know it isn't right, but can anyone provide the correct syntax? Also what If I want to run the rest of the scripts, except the beginFile.sh and the *Backup.sh file (i.e. beginAnother.sh and beginJunk.sh)? Code:
ls /folderpath | grep 'begin[^File.sh]' | xargs -n1 sh Would the expression change because I'm using grep? Thanks in advance for all answers. Last edited by mrwatkin; 12-23-2009 at 03:43 PM.. |
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#2
12-23-2009
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If you set extglob (shopt) to yes in bash, or standard in ksh93 you can do this: Just run beginfile: Code:
/folderpath/beginFile.sh run he rest of the scripts: Code:
/folderpath/!(beginFile.sh) run the rest of the scripts, except the beginFile.sh and the *Backup.sh file Code:
/folderpath/!(beginFile.sh|*Backup.sh) Last edited by Scrutinizer; 12-23-2009 at 04:16 PM.. |
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