awk question - UNIX for Dummies Questions & Answers

google · #1 12-17-2003

Is there a string concatenation function such as the 'C' strcat in awk? If not, how could I accomplish this (using awk)?

Optimus_P · #2 12-17-2003

Quote:

Originally posted by google
Is there a string concatenation function such as the 'C' strcat in awk? If not, how could I accomplish this (using awk)?

i know you said awk. but here is my .02 in perl you can use the "." to concatiniate.

according to this site:

http://www.cs.uu.nl/docs/vakken/st/nawk/nawk_60.html

There is only one string operation: concatenation. It does not have a specific operator to represent it. Instead, concatenation is performed by writing expressions next to one another, with no operator. For example:

fpmurphy · #3 12-17-2003

There is no separate strcat function in awk. String
concatenation is build into the language.

Here is a simple awk script which demonstrates
string concatenation in awk.

BEGIN {
str="strcat"

for (i =0; i < 3; i++)
str = str " demo" i

print length(str), str
}

Hope this helps
- Finnbarr

google · #4 12-17-2003

Code:

echo $PARENT_PATH | awk ' {
     
              arraySize = split($0, parentPath, "/");
              delete parentPath[arraySize];
    
              for (i in parentPath ) {
               w = w parentPath[i];
  
              }
              print w
            }'

I need a quick way to strip the last node of a directory path, given a directory path as input. The code above falls short in that the output does not include the "/" in the path. I need a way to append the "/" between each node. I have tried to do the following:
r = /
w = w r

but awk doesnt like it!

thanks for the help.

google · #5 12-17-2003

Code:

echo $PARENT_PATH | awk ' {
     
              arraySize = split($0, parentPath, "/");
              delete parentPath[arraySize];
    
              for (i in parentPath ) {
               w = w "/" parentPath[i];
  
              }
              print w
            }'

Works. Cool. Thanks for all of your help.

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