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08-19-2009
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If you have a variable year with the value "2009" the awk command should prints lines that contains the pattern 2009 :05 till the line with the pattern 2009 :17.
Does it work or do you get errors? |
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08-19-2009
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it wont gave an error but the process occupied 99 % CPU so i killed it.
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| grep -v, sed awk bash shell |
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