hi, i have a very long text file. i need to extract with grep command a certain part.
for example text file include 1ooo rows:
1....
2...
3...
.
.
.
1000

i want to view with grep only rows 50-100.
any ideas will be appreciated
thanks...

why you want to do it with grep only??
sed,awk many other simple commands can do it.. read the man pages and give it a try..

Hi.

Grep is for searching for specific things. If you only want specific lines, not based on the contents you could, amongst other things, use head and tail..

thanks mate, in order to use your solution i need another piece of the puzzle:
lets say that i know the first row number (e.g. 50) but i need to find out the number of the bigger one. the only clue i have is that row 100 is starting with certain string (x).
between 50-100 x appears only on the 100 row, though after 100 it appears on various rows. do you have an idea how can i locate the number of that row?
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BTW i need this section for manipulating it in my bash script...
if you can help it will be highly appreciated.

Yep, that's good!

And by the same definition, so is

I do love this forum!

thanks folks but it seems the it just opens the file (as cat).

hoped it will retrieve the row's number.

thanks...