du - Disk Usage for only files and NOT directories.

RRVARMA · #1 (**permalink**) 07-01-2009

Hello,

Could any one help me how to find the Disk Usage for all the files in the running directory and the sub directories without the disk usage of the directory. I mean to say, i need only the file names without the size of the directories.

See, i used this command

du -a .|sort -nr|more

here i'm getting even the size of directories. I need only the files in each directory. Could you help me please. Thanks in advance.

Note: I'm using MP-RAS and i find du -l doesn't work out.

------------------------------------
Like to add some more..

I found that ls -lu gives the files in the order that they were accessed (even if it is read and not modified). I'm trying to find some command or simple logic where i can filter the filenames that are large in size and NOT accessed for a longer duration of time.

Even a discussion or clue will also be appreciated. (but it should be genuine please).
Thanks a lot.

jim mcnamara · #2 (**permalink**) 07-01-2009

Let's say you want to see files larger than 100 blocks (block size varies by filesystem but for this example assume 1024 bytes) with an access time older than 15 days.

Code:

find /path/to/files  -type f -atime +15 -size +100 -exec ls -lu {} \;

DukeNuke2 · #3 (**permalink**) 07-02-2009

you can also use a little script like:

Code:

#!/bin/ksh
for i in $(ls)
do
 if [ -f $i ]
 then
  du -sh $i
 fi
done
exit 0

RRVARMA · #4 (**permalink**) 07-09-2009

Hi,,

I got part of the thing done..

i gave this command..

du -as|sort -nr|more

and got all the files.. in the descending order of the file usage.. that was cool.. now wat i need is to bring them in an order these files were accessed..

thanks a lot for your contribution..

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