multiple comparison in awk

paruthiveeran · #1 (**permalink**) 06-17-2009

I have an input file. Each line in it has several characters. If the first three characters of the line is '000' or '001' or '002' or '003', I need to print it in output. How can I do this in awk.

I am able to do if the search string is only one (let us say 000).
cat <filename> | awk 'substr($0,1,3)=="000" {print}'

How do I search for multiple matches? Is there an or condition that I can put after the == sign?

vgersh99 · #2 (**permalink**) 06-17-2009

Code:

awk 'substr($0,1,3) ~ "00[0-3]" ' myFile
OR
awk '/^00[0-3]/' myFile

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