Cut specific fields from a file containing multiline records

sunayana3112 · #1 (**permalink**) 04-12-2009

Hi,
I am looking for a method to get column13 to column 50 data from the 1st line of a multiline reord. The records are stored in a large file and are separated by newline. sample format is

(data in red is to be extracted)

<header>

A001dfhskhfkdsh hajfhksdhfjh shdfhsdfhkjldsfhslkjlshdfsdlfhsd;lh
A002skdjfkjsdkfj kjafjdsljfpok;fjdskf;kldsjfposifpsjdf
A003jlskjfslkfjsljf ;dfs;ksjg
A004sdfhskjlfhlshf jhsfhskjldhfjs

A001dfhskhfkdsh hajfhksdhfjh shdfhsdfhkjldsfhslkjlshdfsdlfhsd;lh
A002skdjfkjsdkfj kjafjdsljfpok;fjdskf;kldsjfposifpsjdf
A003jlskjfslkfjsljf ;dfs;ksjg
A004sdfhskjlfhlshf jhsfhskjldhfjs
.....

<trailer>

radoulov · #2 (**permalink**) 04-12-2009

I don't understand the "column13-50" part but given your example this should work:

[use gawk, nawk or /usr/xpg4/bin/awk on Solaris]

Code:

awk '/^A[0-9]/{print substr($0,30,15)}' RS= infile

krabu · #3 (**permalink**) 04-12-2009

grep ^A001 | cut f15-50

atl@mav · #4 (**permalink**) 04-14-2009

cat filename | grep hajfhksdhfjh | cut -d ' ' | cut -f15-50

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