while loop in /bin/sh

ruben.rodrigues · #1 (**permalink**) 03-11-2009

Hi!

I want my script to enter in a while cicle. And I did a:

var=0

while [$var < 1]
do
echo "while"
done

this is very simple because it's just for testing

So what I think that was suppost to happen was
while
while
while
while
while
while
....
....
while

BUT nothing

what is wrong in my while

thanks

radoulov · #2 (**permalink**) 03-11-2009

Try changing the < operator:

Code:

while [ "$var" -lt 1 ]
do
  echo "while"
done

ruben.rodrigues · #3 (**permalink**) 03-11-2009

Quote:

Originally Posted by radoulov

Try changing the < operator:

Code:

while [ "$var" -lt 1 ]
do
  echo "while"
done

thanks, it works but not in my script because it says line 29 [0: not found (????)
so my code is:

Quote:

#!/bin/sh

var=0
echo $var
LOGFILE=`mktemp -t svn_checkout.XXXXXX`
ICONPATH="`dirname $0`/svn.xpm"
list=`ssh ruben@192.168.1.3 "ls /esp-server/svn"`
URL=`zenity --entry --title="Subversion: Checkout" --text="$list

Enter repository folder according to the the aboves:" --entry-text="" --width=400 --window-icon="$ICONPATH" 2>&1`

if [ $? -eq 0 ] ; then
svn checkout svn+ssh://ruben@192.168.1.3/esp-server/svn/$URL &> $LOGFILE & pid1=$!
echo $pid1
zenity --progress --pulsate --auto-kill & pid2=$!
echo $pid2
DIR=/proc/$pid1
echo $DIR
while [$var -lt 1]
do
echo "while"
if [ -d $DIR ] ; then
echo "does exist"
else
echo "does not exist"
fi
done
rm -f $LOGFILE
fi
echo "end"

and my line 29 is the last fi. And I have a lot of echo to show me the status.
Now I realy don't know why it doesn't enter in the while
Can you help me??

thanks

radoulov · #4 (**permalink**) 03-11-2009

Change this:

Code:

[$var -lt 1]

to this

Code:

[ $var -lt 1 ]

You need a space after the opening bracket and another one before the closing one.

ruben.rodrigues · #5 (**permalink**) 03-11-2009

Quote:

Originally Posted by radoulov

Change this:

Code:

[$var -lt 1]

to this

Code:

[ $var -lt 1 ]

You need a space after the opening bracket and another one before the closing one.

MANNNNNN no way. lol I lost sooooo many time and was just a space. lol

thanks

ruben.rodrigues · #6 (**permalink**) 03-11-2009

other thing
here:
if [ -d $DIR ] ; then

how can I use a not
like -d $DIR but negative

radoulov · #7 (**permalink**) 03-11-2009

Code:

[ ! -d "$DIR" ]

or

Code:

[ -d "$DIR" ] || ...

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