How to find one partucular user logs when there are lots of users running on it - UNIX for Advanced & Expert Users

ksr.test · #1 10-06-2008

On my application there are lots of users are doing there work or tasks? ...In my SSH or in 'Putty' i am observing logs?
Hot to observe one particular 'user' logs.. even through there are lots of users working on it?

For EX: i am log in with use rid:nikhil@in.com. another one log in with john@in.com another one with another uid,pwd... etc i am doing my business on it like that another one doing their business? But under logs the contents is comming continuosly like mixed with all other users .... here i want to see only contents of login with my useid here it is nikhil@in.com.

my commands for seeing logs are here : tail -f logs/application.log

logs is dir
application.log is logs file.

it would be appreciated if any one help in this regard..

nua7 · #2 10-06-2008

well it would depend, on how the data is logged.

You might be having the user name logged in the log file. Why don;t you grep the log file on that particular user.

otheus · #3 10-06-2008

You can just grep the output of tail:

Code:

USER=john
RHOST=in.com
tail -f logs/application.log | grep "user $USER"

The other thing you can do is install pam_script and set up a "onsessionopen" and "onsessionclose" script which will generate such a logfile, and is guaranteed to run (unless sshd is killed with -9).

ksr.test · #4 10-06-2008

Quote:

Originally Posted by otheus

You can just grep the output of tail:

Code:

USER=john
RHOST=in.com
tail -f logs/application.log | grep "user $USER"

The other thing you can do is install pam_script and set up a "onsessionopen" and "onsessionclose" script which will generate such a logfile, and is guaranteed to run (unless sshd is killed with -9).

by above grep command we are getting the lines which contains that particular user id right ?

otheus · #5 10-07-2008

Quote:

Originally Posted by ksr.test

by above grep command we are getting the lines which contains that particular user id right ?

Yes. .

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