Hi,

I would like to setup a FOR loop script to find out all the existing linux workstation in the network w/ ip address, hostname and linux version.

I created a basic FOR loop script:

for i in $(seq 1 254)
do
echo 10.72.169.$i >> result
ssh -o ConnectTimeout=3 root@10.72.169.$i "hostname" >> result
ssh -o ConnectTimeout=3 root@10.72.169.$i "cat /etc/redhat-release" >> result
done


However, the output is like this:

.
.
10.72.169.21
lumines.devo.ilx.com
Fedora Core release 5 (Bordeaux)
10.72.169.22
10.72.169.23
10.72.169.24
copper.devo.ilx.com
10.72.169.25
frogger.devo.ilx.com
Fedora Core release 5 (Bordeaux)
10.72.169.26
afterlife.devo.ilx.com
Red Hat Linux release 9 (Shrike)
10.72.169.27
10.72.169.28
molybdenum
Red Hat Linux release 9 (Shrike)
10.72.169.29
Red Hat Linux release 7.2 (Enigma)
10.72.169.30
.
.
.

I want the output to be like :

10.72.169.21 lumines.devo.ilx.com Fedora Core release 5 (Bordeaux)
10.72.169.22 abc.devo.ilx.com Fedora Core release 5 (Bordeaux)
.
.

I think with the command AWK, i can do that. But I don't know how to make it to work. Can someone show it to me?

Thanks
BEELOO

Sorry, it doesn't work. it said:

test2: line 3: unexpected EOF while looking for matching `''
test2: line 5: syntax error: unexpected end of file

Yeah, sorry, I left that off, you need one more backquote at the very end of the long line.

First of all it's bad practice to allow root logins via ssh. You have been warned ...

There's a backtick (`) missing at the end of the echo line.

(a better looking option would be the following inside the loop (no redirection at the end of the loop then)

echo -n 10.72.169.$i >> result
ssh -o ConnectTimeout=3 root@10.72.169.$i "hostname; cat /etc/redhat-release" >> result