How to filter the words, if that word contains the expected letter - UNIX for Advanced & Expert Users

venu_eie · #1 (**permalink**) 03-18-2008

Hi,

I am trying to filter the words from a file which contain 'abc'. But I am unable to. Could any one help me.

For eg: The file contents are

123ab 12hnj1 123abc456 123cgbcahjkf23 23134abchfhj43 gc32abc abc1 2abc3 sd uiguif fhwe 21242 uh123 jkcas124d123 u3hdbh23u ffsd8

Output expecting is :
123abc456 23134abchfhj43 gc32abc abc1
2abc3

Regards
Venu

permalink · #2 (**permalink**) 03-18-2008

Your example is not very clear. You mean, extract and print those tokens which contain the string "abc"?

Code:

vnix$ perl -lane 'print join (" ", grep { /abc/ } @F)'
foo fabci canbc cabca fnabca 123ab23c babco swill <- input
fabci cabca fnabca babco
snort abc foo <- input
abc
^D

Do you want to preserve newlines? (This solution does.) What about spaces between the tokens? (This solution normalizes them to one space between each.)

radoulov · #3 (**permalink**) 03-18-2008

With Z-Shell:

Code:

print ${(M)$(<file)##*abc*}

venu_eie · #4 (**permalink**) 03-19-2008

Hi era,

Your solution is in perl, I need it in unix.

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