guys forget the find command coz with find command u can't get condational output like grep. I will give small example :-


Apr 10 09:12 aacbl222_12aug1998.lqc
Apr 10 09:12 sscbl4534_4sep2001.lqc
Apr 10 09:12 ah66fmi_5jan1997.lqc
Apr 10 09:12 y313h1_7sep1998.lqc
May 11 09:12 aalike_9aug2000.lqc

all this files and thosands more in /test/test2
to get my file I should give some parameter " in this example I give 2 gre some time it will take more than 6 grep's to get what I want " forget it "
--------------------------------------------------

ls -lrt | grep "Apr 10" | grep 1998

Apr 10 09:12 y313h1_7sep1998.lqc
Apr 10 09:12 aacbl222_12aug1998.lqc

--------------------------------------------------

now when I want to print what I got from my command I will do this : -

print y313h1_7sep1998.lqc ; print aacbl222_12aug1998.lqc

when I type

ls -lrt | grep "Apr 10" | grep 1998 | lp
I will get the printe of result not the file it self...Pleassse try to understand me and execuse me for my "GOOD" english

Better to read all what I wrote above or just read this

[ HOW I CAN PRINT THE RESULTED FILES AS A FILE NOT AS OUTPUT ]

Havent I already answered the question?..

Or Was the command unsuccessful?

The answer is...

pipe the output in a file

ls > FILE.txt

creates or if exists overwrites the file FILE.txt and stores the output of the ls command in it.

ls >> FILE.txt appends the output of the command if the file exists or create a new one if not


hope this solves your problem




see the other thread as well

Frank

Please try to understand me

ls | grep "bla bla bla" >> result.txt

ok I will get the result in result.txt as u said then I want to print the files, don't tell me to print result.txt coz I will get in name of the file in the print out and I want to print the information inside the file.It's very simple please don't make me feel my english toooo BAD & unix As well

what I want is the fastest way to print multipul files

what I'm using right now is

print file1 ; print file2 ; print file3 ; print file4

Please please read this carefully and try it out before deciding it won't work, because as far as I can tell, it will!

I think that if you can figure out exactly what you are needing to do (which files to print, and when), you could use a very simple find command to do it.
But if you really really really want to use grep a bunch of times, you could do this:

ls -ltr | grep "Apr 10*1998.lqc" > /tmp/lp_file
print `cat /tmp/lp_file`

for each in `cat /tmp/lp_file`; do print $each; done

for each in *sep2001.lcq; do; print $each; done

ls -lrt | grep "Apr 10*1998.lqc" | xargs print

ls -lrt | grep "Apr 10*1998.lcq" > /tmp/lp_list
for each in `cat /tmp/lp_list; do print $each; done

Or even the basic step of taking the file.txt and adding print in the beginning of each line in the file and making it exe.

I know this is horrible scripting, but it works.

I agree that one of Livinfree's suggestions will work. see below his code.

code:
--------------------------------------------------------------------------------
for each in `cat /tmp/lp_file`; do print $each; done
--------------------------------------------------------------------------------