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09-21-2007
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Find File names with sustitution
Hi All,
Iam trying to find two kinds of files while ignoring rest of the files in a directory The files are like below Files to be found -------------------- perp45560 oerp4556 Files to be ignored ---------------------- oerp4556123450 oerp4556123470 I was trying the following in SunOS 5.10 find /mydir/files -name "[po]erp4556[?]" it is NOT working if i use find /mydir/files -name "[po]erp4556*" it lists the files to be ignored also if i use find /mydir/files -name "[po]erp4556[0]" it lists only "p" kind of files and ignores "o" kind. the problem is simple while "p" files have a "0" [Read as zero] at the end, "o" files dont have anything. How to write a find command to find both simultaeneously while it should ignore other longer "p" or "o" files. I would appreciate your help. Regards |
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09-21-2007
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-name only knows shell patterns..
Code:
find /path \( -name perp* -o -name oerp* \) -ls |
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09-21-2007
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1.
Code:
$ ls oerp4556 oerp4556123450 oerp4556123470 perp45560 $ find . -name 'oerp4556' -o -name 'perp45560' ./perp45560 ./oerp4556 Code:
$find -regextype posix-extended -regex '.*[op]erp45560{,1}'
./oerp4556
./perp45560
2. With ksh,bash and zsh you can use ksh or extended-globbing, but you can do a recursive search only with the Z-Shell: [ksh] Code:
$ echo * oerp4556 oerp4556123450 oerp4556123470 perp45560 $ echo [op]erp4556?(0) oerp4556 perp45560 Code:
bash 3.2.25(1)$ shopt -s extglob bash 3.2.25(1)$ echo [op]erp4556?(0) oerp4556 perp45560 [zsh] Code:
zsh 4.3.4% setopt kshglob zsh 4.3.4% echo [op]erp4556(?(0)) oerp4556 perp45560 Code:
setopt kshglob print -l **/[op]erp4556(?(0)) |
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09-26-2007
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Quote:
find /mydir/files -name "[po]erp4556?" |
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09-26-2007
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Quote:
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