Reposting, as it got lost during the database backup.

Via a shell script a spawn 3 background jobs namely a, b & c.

These will take different times to complete.

I want to print a different message on completion of each.

How can i find out when each one has completed independently.

Thanks

Create a wrapper script for each task that prints the message when the wrapper completes. Then have the main script spawn each wrapper instead.

Wrapper script

Hi,
Does this approach helps?.

Gurus,
Please provide suggestions.

#!/bin/ksh
LOG_FILE=/tmp/${0##*/}.log

LogMsg() {
 print "$(date +%d/%m/%y:%H:%M:%S) : $@"  >> $LOG_FILE
}

CallA() {
 LogMsg "Calling Function A"
 iostat 5 5  >> $LOG_FILE &
 wait $!
 LogMsg "A done with $!"
 return 45
}

CallB() {
 LogMsg "Calling Function B"
 vmstat 5 5  >> $LOG_FILE &
 wait $!
 LogMsg "B done with $!"
 return 46
}

Main() {
 LogMsg "Starting the Process - Main"
 CallA
 Ret=$?
 LogMsg " Returned value $Ret "
 CallB
 Ret=$?
 LogMsg " Returned value $Ret "
}

# Call the Main Function here
Main

But on calling CallA, the control won't return to Main till it ends, as wait ?! will wait for it.

I have to spawn all things simultaneously.

BTW what's
${0##*/}

why cant you...

start A
start B
start C
wait

where each of A, B and C do the following

print a line saying they have started
run the task
print a line saying they have ended