Im trying to replace every line

line1
line2
line3

with:

line1
extraline1

line2
extraline2

line3
extraline3


with about 10 extra lines
I am able to add axtra lines with:

sed '/[^ ]*/ a\\
new line\\
' file > newfile

but i want the name of the original line in the new lines,
I have tried using '&' eg:

sed '/[^ ]*/ a\\
extra&\\
' file > newfile

but it outputs the & symbol and not the original line!

Can anyone help me?

try:
sed 's/\(.*\)/\1\nextra\1/'

Thanks, that works for the first line, but i want to create a second line with the first line in it. And the following code doesnt work.

sed -e 's/\(.*\)/\1\nextra\1/' -e '/\(.*\)/ a\\
nextra\1\nextra/1/\\
' test > temp

The result is:

filename1.ADFnextrafilename1.ADF
nextra1nextra/1/

Can you help?

Hmmm:

file:
line1
line2
line3

cat file|sed 's/\(.*\)/\nextra\1/'>newfile

cat newfile
line1
extraline1
line2
extraline2
line3
extraline3

Maybe I don't understand what you actually want to do.

Yeah thats exactly what I want!
But for some reason, when I run it, i get:

file:
line1
line2
line3

cat file|sed 's/\(.*\)/\nextra\1/'>newfile

cat newfile:
nextraline1
nextraline2
nextraline3

Do you have any idea why?

check that the \ is in front on the n

sed 's/\(.*\)/\1\nextra\1/'

Alternative in Python:

>>> extralines = ['extraline1','extraline2','extraline3']
>>> lines = ['line1','line2','line3']
>>> zip(lines,extralines)
[('line1', 'extraline1'), ('line2', 'extraline2'), ('line3', 'extraline3')]
>>> for i in zip(lines,extralines):
... 	print '\n'.join(i)
... 	
line1
extraline1
line2
extraline2
line3
extraline3