conversion - UNIX for Advanced & Expert Users

rajan_ka1 · #1 (**permalink**) 03-14-2006

Dear friends,

i am writing sh shell script

I have a file containing binary data.

like this.

010101010101010101101010101010100001010101010101001.

i want to read some particular bits and convert it into decimal valuse.

example.

1.first i want to read 5 bits and convert it into decimal.
2. next i have to take from 6 bit to 12 bit ie 6 bits in to decimal value.

how it is possible in unix.

please provide code.

thanks in advance.

thestevew · #2 (**permalink**) 03-14-2006

You don't say how you choose which parts of the binary data to convert, so I've put in some code to get start position and length (replace this with your real selection criteria) and pipe the result through bc (which handles preposterously long numbers) to do the actual conversion:

Code:

data="010101010101010101101010101010100001010101010101001"
while :
do
  read s?"Start bit (1..n): "
  read l?"Length          : "
  x=$(expr substr $data $s $l)
  r=$(print "ibase=2;obase=A; $x" | bc)
  print Result $r
  print "Press ^C to quit"
done

hope this helps

cheers

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